Answer:
V =[tex]\frac{2\pi(b^{3} -a^{3}) }{3}[/tex]
Step-by-step explanation:
using spherical cordinates :
region is 0≤θ≤2π,0≤ϕ≤π/2,a≤ρ≤b
dV=ρ2sinϕ dρ dϕ dθ
Volume,V=∫[0 to 2π] ∫[0 to π/2] ∫[a to b] dV
=>V=∫[0 to 2π] ∫[0 to π/2] ∫[a to b] ρ2sinϕ dρ dϕ dθ is the integral in appropriate coordinates
=>V=∫[0 to 2π] ∫[0 to π/2] |[a to b] (1/3)ρ3sinϕ dϕ dθ
=>V=∫[0 to 2π] ∫[0 to π/2] (1/3)(b3-a3)sinϕ dϕ dθ
=>V=∫[0 to 2π] |[0 to π/2] (1/3)(b3-a3)(-cosϕ) dθ
=>V=∫[0 to 2π] (1/3)(b3-a3)((-cos(π/2))-(-cos0)) dθ
=>V=∫[0 to 2π] (1/3)(b3-a3)((0)-(-1)) dθ
=>V=∫[0 to 2π] (1/3)(b3-a3)dθ
=>V=|[0 to 2π] (1/3)(b3-a3)θ
=>V= (1/3)(b3-a3)(2π-0)
V =[tex]\frac{2\pi(b^{3} -a^{3}) }{3}[/tex]