Question

A diver steps off a diving platform. How fast will she be moving when she
reaches the water 10.0 m below?
A. 7.00 m/s
B. 9.90 m/s

c. 14.0 m/s

D. 196 m/s

Answer 1

Answer:

C. 14.0 m/s

Explanation:

$v_0=0\\a=g=9.9.8\\h=10\\v_f=?$

$v_f^2=v_0^2+2a \Delta h\\v_f=\sqrt{v_0^2+2a \Delta h}\\v_f=\sqrt{0+2(9.8)(10)}\\v_f=\sqrt{196}\\v_f=14$