Question

Se lanza un objeto desde una plataforma.
Su altura (en metros), xxx segundos después del lanzamiento, está modelada por:
h(x)=-5x^2+20x+60h(x)=−5x
2
+20x+60h, left parenthesis, x, right parenthesis, equals, minus, 5, x, squared, plus, 20, x, plus, 60
¿Cuál es la altura del objeto en el momento del lanzamiento?

Answer 1

Answer:

The height of the object at launch is 60 meters.

Step-by-step explanation:

The question is:

An object is thrown from a platform.  Its height (in meters), x seconds after launch, is modeled by h (x) = - 5x^2 + 20x + 60. What is the height of the object at launch?

Solution:

The equation representing the height of the object x seconds after launch from the platform is:

$h (x) = - 5x^{2} + 20x + 60$

In this case we need to compute the height of the object at launch, i.e. the height of the object at x = 0 seconds.

Compute the height of the object at x = 0 seconds as follows:

$h (x) = - 5x^{2} + 20x + 60\\=-(5\times 0^{2})+(20\times 0)+60\\=60$

Thus, the height of the object at launch is 60 meters.