Question

The pressure at 10 {\rm m} below the surface of the ocean is about2.00×105Pa.Which of the following statements istrue?The weight of a column of seawater 1{\rm m}^2 in cross section and 10 {\rm m} high is about 2.00×105\rm N.The weight of a column of seawater 1{\rm m}^2 in cross section and 10 {\rm m} high plus the weight of a column of air with thesame cross section extending up to the top of the atmosphere isabout 2.00×105\rm N.The weight of 1 {\rm m}^3 of seawater at 10 {\rm m} below the surface of the ocean is about2.00×105\rm N.The density of seawater is about2.00×105 times the density of air at sealevel.

Answer 1

Complete Question

The pressure at 10 {\rm m} below the surface of the ocean is about 2.00×105Pa. Which of the following statements is true?

Option 1=>The weight of a column of seawater 1{\rm m}^2 in cross section and 10 {\rm m} high is about 2.00×105\rm N.

Option 2=>The weight of a column of seawater 1{\rm m}^2 in cross section and 10 {\rm m} high plus the weight of a column of air with the same cross section extending up to the top of the atmosphere is about 2.00×105\rm N.

Option 3=>The weight of 1 {\rm m}^3 of seawater at 10 {\rm m} below the surface of the ocean is about 2.00×105\rm N.

Option 4=>The density of seawater is about 2.00×105 times the density of air at sealevel.

Answer:

The correct option is  2

Explanation:

     From the question we are told that

    The height is  $h = 10 m$

      The pressure is  $P_{T} = 2.00*10^{5}\ Pa$

Generally pressure is mathematically represented as

        $P = FA$

The force (i.e the weight ) on the column of the seawater due to the pressure can be mathematically evaluated as

       $F = \frac{P}{A}$   fff

Here the  Area is  $A = 1m^2$ as stated in the question

      $F = \frac{2*10^{5}}{1}$

          $F = 2.0*10^{5} N$