Question

The drawing shows a current-carrying wire lying along the x axis. The current I is 3.0 A and flows to the right. The wire is 0.43 m long and situated in a uniform magnetic field B. The magnetic field points along the z axis and has a magnitude of 2.0 T. What is the magnitude F and direction of the magnetic force exerted on the current? F = N

Answer 1

Answer:

The force is 2.58N

The direction of the force at 90° to the conductor

Explanation:

N/B I can't find any attachment for my reference

But this problem bothers on the force on a current carrying conductor

In accordance with the Flemings left hand rule the conductor will experience a force perpendicular to it

F= BILsinθ

Given data

Current I = 3 amps

Length of the conductor L= 0.43m

Magnetic field B= 2T

Angles between conductor and magnetic field θ= 90°

Substituting our data into the expression for force we have

F= 2*3*0.43

F= 2.58N

The direction of the force at 90° to the conductor