Question

The distance d (in inches) that a ladybug travels over time t

(in seconds) is given by the function d (t) =ť – 2t +2. Find

the average speed of the ladybug from ti = 1 second to

t2 = 3 seconds.

inches/second

Answer 1

Answer:

The average speed of the ladybug from t = 1 second to t = 3 seconds is 4 m/s.

Step-by-step explanation:

The distance d that a ladybug travels over time t is given by :

$d(t)=t^2-2t+2$

Here,

d is in inches

t is in seconds

Let v is the speed of the ladybug. It is given by :

$v=\dfrac{d(t)}{t}\\\\v=\dfrac{d(t^2-2t+2)}{dt}\\\\v=2t-2$

At t = 1 second, v = 2(1) -2 = 0

At t = 3 seconds, v = 2(3) -2 = 4 m/s

So, the average speed of the ladybug from t = 1 second to t = 3 seconds is 4 m/s.

Answer 2

The average speed of the ladybug from t = 1 second to t = 3 seconds is 2 inches/second.

Given distance is: $d (t) =t^2 - 2t +2$

At t = 1 second,  $d (1) =1^2 - 2(1) +2=1$

At t = 3 seconds, $d(3)=3^2 - 2(3) +2=5$

So, the average speed of the ladybug from t = 1 second to t = 3 seconds is $\frac{v\left(3\right)-v\left(1\right)}{3-1}=\frac{5-1}{2}=\frac{4}{2}=2$  inches/second.

Find out more information about the average speed here:

https://brainly.com/question/4931057