Respuesta :
Answer:
IQ score of 102.55
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score, measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value, which is also the shaded area under the curve, is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 100, \sigma = 15[/tex]
The shaded area under the curve is 0.5675.
This means that Z has a pvalue of 0.5675.
So, we have to find X when Z = 0.17.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]0.17 = \frac{X - 100}{15}[/tex]
[tex]X - 100 = 15*0.17[/tex]
[tex]X = 102.55[/tex]
IQ score of 102.55
Using the Zscore formula, the indicated IQ score of the normally distributed data is 102.25
- Using the normal distribution table ; 0.5675 has a Zscore which corresponds to 0.17
Recall :
Zscore = (Score - Mean) / standard deviation
0.17 = (Score - 100) / 15
15 × 0.17 = Score - 100
2.25 = score - 100
Score = 100 + 2.25
Score = 102.25
Therefore, the indicated IQ score is 102.25
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