Answer:
[tex]\dfrac{2}{3}\pi r^3 $ cubic units[/tex]
Step-by-step explanation:
Given a cone of base radius, r and perpendicular height, h
[tex]\text{Volume of the cone }=\frac{1}{3}\pi r^2 h[/tex]
Since the height of a cone is twice the radius of its base.
[tex]\text{Volume of the cone }=\dfrac{1}{3}\pi r^2 (2r)\\=\dfrac{2}{3}\pi r^3 $ cubic units[/tex]
The expression that represents the volume of the cone, in cubic units is [tex]\dfrac{2}{3}\pi r^3 $ cubic units[/tex].