Question

g Use technology to find the​ P-value for the hypothesis test described below. The claim is that for a smartphone​ carrier's data speeds at​ airports, the mean is mu μ equals = 17.00 17.00 Mbps. The sample size is n equals = 22 22 and the test statistic is t equals = negative 1.576 −1.576.

Answer 1

Answer:

The sample size is n = 22. So then we can find the degrees of freedom given by:

$df = n-1= 22-1 =21$

And since is a bilateral test we can find the p value with this:

$p_v = 2* P(t_{21}< -1.576) = 0.130$

And the excel code to find it is : "=2*T.DIST(-1.576,21,TRUE)"

Step-by-step explanation:

For this case we have the following system of hypothesis:

Null hypothesis: $\mu = 17$

Alternative hypothesis: $\mu \neq 17$

So we are conducting a bilateral test. We know that after find the statistic for this case we got $t= \pm 1.576$

The sample size is n = 22. So then we can find the degrees of freedom given by:

$df = n-1= 22-1 =21$

And since is a bilateral test we can find the p value with this:

$p_v = 2* P(t_{21}< -1.576) = 0.130$

And the excel code to find it is : "=2*T.DIST(-1.576,21,TRUE)"