Question

For similar light intensity, compact fluorescent bulbs use about 25% of the energy of incandescent bulbs. Let's say you replaced a bulb of 100 W with a fluorescent bulb and that your utility charges $0.15/kW-hour. How many dollars would you save in electricity in the 10,000−hour lifetime of the bulb?

Answer 1

Answer:

$112.50¢

Step-by-step explanation:

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Answer 2

$112500 would be saved in electricity in the 10,000−hour lifetime of the Fluorescent bulb.

Given that compact fluorescent bulbs use about 25% of the energy of incandescent bulbs.

Hence, For a 100W bulb, the corresponding energy is:

Fluorescent bulb = 25% of 100W = 0.25 * 100 = 25W

Since the charges is $0.15/kW-hour, hence, for 10000 hour lifetime:

Total charges for  Incandescent = 100W * 10000 hour * $0.15/kW-hour = $37500

Total charges for Fluorescent = 25W * 10000 hour * $0.15/kW-hour = $150000

Therefore the money saved in electricity = $150000 - $37500 = $112500

Hence $112500 would be saved in electricity in the 10,000−hour lifetime of the Fluorescent bulb.

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