The surface area of the given pyramid is [tex]2124112 m^{2}[/tex].
"The surface area of a pyramid is a measure of the total area that is occupied by all its faces."
The base of the square pyramid is 230 meters by 230 meters.
Therefore, the base area of the pyramid is
[tex]= (230)^{2} m^{2} \\= 52900 m^{2}[/tex]
The perimeter of the base
[tex]= 4(230) m\\=920 m[/tex]
Therefore, the lateral surface area of the pyramid
[tex]= \frac{1}{2}[/tex] × perimeter × slant height
[tex]= \frac{1}{2}(920)(187) m^{2} \\= 2071212 m^{2}[/tex]
Therefore, the surface area of the pyramid is
= Base area + lateral surface area
[tex]= (52900 + 2071212)m^{2} \\= 2124112 m^{2}[/tex]
Learn more about the surface area of a pyramid here: https://brainly.com/question/1503383
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