Question

Two electrically opposite charges are separated by a fixed distance. Which action will provide the greatest increase in the force of attraction between the charges?

Answer 1

Explanation:

The electric force between charges is given by the formula as follows :

$F=\dfrac{kq_1q_2}{r^2}$

k is electrostatic constant

r is distance between charges

Here, charges are equal and opposite. So,

$F=\dfrac{kq^2}{r^2}$

It is clear the force is inversely proportional to the distance between charges and directly proportional to the product of charges. So, greatest force will be providing by :

• Increasing the magnitude of charges
• Decreasing the distance between charges.