Answer:
[tex]120\pi[/tex] square units
Step-by-step explanation:
We are given that
Radius of circle=12 units
Angle MLK=60 degree
We have to find the area of sector that is not shaded.
Area of shaded sector MLK=[tex]\frac{\theta}{360}\times \pi r^2[/tex]
Area of shaded sector MLK=[tex]\frac{60}{360}\times \pi(12)^2=[/tex]24 square units
Area of whole circle=[tex]\pi r^2=\pi (12)^2=144\pi[/tex]square units
Area of sector that is not shaded =Area of whole circle-Area of shaded sector MLK=[tex]144\pi-24\pi[/tex]
Area of sector that is not shaded=[tex]120\pi[/tex] square units
