Question

A bag contains 5 red, 4 green, and 3 blue marbles. What is the probability of randomly picking a green marble, replacing it, and then randomly picking a blue marble?

Answer 1

Answer:

1/11

Step-by-step explanation:

4/12 probability for 4 and you don't replace it so 3/11 for blue. multiply across is  12/132=1/11

Answer 2

The probability of randomly picking a green marble, replacing it, and then randomly picking a blue marble is 1/11.

Given that,

A bag contains 5 red, 4 green, and 3 blue marbles.

We have to determine,

What is the probability of randomly picking a green marble, replacing it, and then randomly picking a blue marble?

According to the question,

These are independent events, so you multiply the probability of each.

Since the marbles are replaced, the probabilities are:

Total number of marbles = 5 + 4 + 3 = 12 marbles

The probability of picking green marble is,

$\rm Probaility (Green) = \dfrac{Number \ of \ green \ marbles} {Total \ number \ of \ marble} \\\\ Probaility (Green) =\dfrac{4}{12}\\\\\rm Probaility (Green) =\dfrac{1}{3}$

And The probability of picking blue marble is,

$\rm Probaility (Blue) = \dfrac{Number \ of \ blue \ marbles} {Total \ number \ of \ marble} \\\\ Probaility (Blue) =\dfrac{3}{11}$

Therefore,

the probability of randomly picking a green marble, replacing it, and then randomly picking a blue marble is,

$= {\dfrac{\dfrac{1}{3}}{\dfrac{3}{11}} }\\\\\\ =\dfrac{1}{3} \times \dfrac{3}{11}\\\\= \dfrac{1}{11}$

Hence, The probability of randomly picking a green marble, replacing it, and then randomly picking a blue marble is 1/11.

For more details refer to the link given below.

https://brainly.com/question/18660021