Answer:
Volume of water left in the cylinder=[tex]76\frac{2}{3}\pi \:in^3[/tex]
Step-by-step explanation:
Height of the Cylinder=10 inches
Radius of the cylinder=4 Inches
Volume of the Cylinder
[tex]=\pi r^2h\\=4^2*10\pi\\=160\pi\:in^3[/tex]
Radius of the Hemisphere=5 Inches
[tex]\text{Volume of a Hemisphere}=\frac{2}{3}\pi r^3\\ =\frac{2}{3}\pi *5^3\\=\frac{250\pi}{3} in^3[/tex]
Since the Volume of the cylinder is greater than the Volume of the bowl, all the water will not fit.
[tex]\text{Therefore: volume of water left} =160\pi-\frac{250\pi}{3}\\=76\frac{2}{3}\pi \:in^3[/tex]