Question

2. Two charges are attracted to each other with a force of eight units. If the charge of one of the two
doubles and the distance between the two objects remains the same, what will be the new force of
attraction between the two objects? Explain your answer.

Answer 1

Answer:

16

Explanation:

The formula for the force of attraction between two charges is $\frac{k\cdot q_1q_2}{r^2}$, where k is a constant, $q_1$ is the first charge, and $q_2$ is the second charge. As you can see, if the radius or distance increases by 2, the force decreases by 4 because it grows exponentially. However, if the charge of one of the particles increases by 2, the force between the two also increases by 2. Therefore, the new force will be 8*2=16. Hope this helps!

Answer 2

The new force of attraction between the two objects is;

F_new = 2F

The formula for force of attraction between two objects is;

F = kq1•q2/r²

Where;

k is coulombs constant

q1 is charge of first object

q2 is charge of second object

r is distance between both objects

Now we are told that the charge of one of the two object doubles and the distance between them remains the same.

This means q1 is now 2q1.

Thus;

F_new = k(2q1) × q2/r²

>> F_new = 2(kq1•q2/r²)

Thus, new force of attraction between both objects will be twice the initial force of attraction which is 2F.

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