Question

If you double a number and then add 32​, you get two ninths
of the original number. What is the original​ number?

Answer 1

Answer:

The number is -18

Step-by-step explanation:

Let x be the original number

2x +32 = 2/9x

Multiply each side by 9 to get rid of the fractions

9(2x +32) =9* 2/9x

18x +288 = 2x

Subtract 18x from each side

18x-18x+288 = 2x-18x

288 = -16x

Divide each side by -16

288/-16 = -16x/-16

-18 =x

Answer 2

Answer:

–18

Step-by-step explanation:

let the number is $x$, from the problem we know that

$2x+32=\frac{2}{9}x

\\9x+144=x

\\x=-\frac{144}{8}=-18$