Question

Find a numerical value of one trigonometric function of x if sin x cot x = 1/3

Answer 1

Answer:

$cosx=0.33$

Step-by-step explanation:

We are given that

$sinxcotx=\frac{1}{3}$

We have to find the numerical value of one trigonometric function.

We know that

$cotx=\frac{cosx}{sinx}$

Using the formula then we get

$sinx\times \frac{cosx}{sinx}=\frac{1}{3}$

$cox=\frac{1}{3}$

$cosx=0.33$

Hence, the numerical value of one trigonometric function

$cosx=0.33$

Answer 2

Answer: see below

Step-by-step explanation:

sin x cotx = sin x * cos x / sin x  = cos x

so cos x = 1/3