Question

Find the area under the standard normal distribution curve between z=0 amd z=1.38

Answer 1

Answer:

$P(0<z<1.38) = P(Z<1.38) -P(Z<0)$

And using the normal standard distribution table or excel we got:

$P(0<z<1.38) =0.916-0.5= 0.416$

The excel code would be:

"=NORM.DIST(1.38,0,1,TRUE) -=NORM.DIST(0,0,1,TRUE)"

Step-by-step explanation:

For this case we know that our random variable of interest is Z and the distribution is given by:

$Z \sim N(\mu =0 , \sigma =1)$

This distribution is an special case of the normal distribution.

And we want to find this probability:

$P(0<z<1.38)$

And we can find this probability with this difference and using the concept of cumulative distribution function for a continuous distribution:

$P(0<z<1.38) = P(Z<1.38) -P(Z<0)$

And using the normal standard distribution table or excel we got:

$P(0<z<1.38) =0.916-0.5= 0.416$

The excel code would be:

"=NORM.DIST(1.38,0,1,TRUE) -=NORM.DIST(0,0,1,TRUE)"