Question

Find the molarity of 186.55 g of sugar (C12H22O11) in 250. mL of water.

Answer 1

Answer:

The molarity of this sugar solution in water is 2.18 M

Explanation:

Step 1: Data given

Mass of sugar (C12H22O11) = 186.55 grams

Molar mass of C12H22O11 = 342.3 g/mol

Volume of water = 250.0 mL = 0.250 L

Step 2: Calculate moles sugar

Moles sugar = mass sugar / molar mass sugar

Moles sugar = 186.55 grams / 342.3 g/mol

Moles sugar = 0.545 moles

Step 3: Calculate molarity of the sugar solution

Molarity = moles sugar / volume of water

Molarity = 0.545 moles / 0.250 L

Molarity = 2.18 MThe molarity of this sugar solution in water is 2.18 M

Answer 2

The molarity of 186.55 gof sugar (C₁₂H₂₂O₁₁) in 250 mL of water is 2.18 M

How to determine the mole of C₁₂H₂₂O₁₁

• Molar mass of C₁₂H₂₂O₁₁ = (12×12) + (22×1) + (11×16) = 342 g/mol
• Mass of C₁₂H₂₂O₁₁ = 186.55 g

• Mole of C₁₂H₂₂O₁₁ =?

Mole = mass / molar mass

Mole of C₁₂H₂₂O₁₁ = 186.55 / 342

Mole of C₁₂H₂₂O₁₁ = 0.545 mole

How to determine the molarity

• Mole of C₁₂H₂₂O₁₁ = 0.545 mole
• Volume = 250 mL = 250 / 1000 = 0.25 L

• Molarity =?

Molarity = mole / Volume

Molarity = 0.545 / 0.25

Molarity = 2.18 M

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