Question

For the reaction shown, calculate how many moles of NH3 form when 16.72 moles of reactant completely reacts:


3 N2H4 (l)

⟶

4 NH3(g) + N2(g)

Answer 1

Answer : The moles of $NH_3$ formed are, 22.3 moles.

Explanation : Given,

Moles of $N_2H_4$ = 16.72 mol

The given chemical reaction is:

$3N_2H_4(l)\rightarrow 4NH_3(g)+2N_2(g)$

From the balanced chemical reaction, we conclude that:

As, 3 moles of $N_2H_4$ react to give 4 moles of $NH_3$

So, 16.72 moles of $N_2H_4$ react to give $\frac{4}{3}\times 16.72=22.3$ moles of $NH_3$

Therefore, the moles of $NH_3$ formed are, 22.3 moles.