Respuesta :
Let x represent amount borrowed at 4.2% and y represent amount invested at 6.8%.
We have been given that Michelle borrows a total of $2500 in student loans from two lenders. We can represent this information in an equation as:
[tex]x+y=2500...(1)[/tex]
[tex]y=2500-x...(1)[/tex]
We are also told that at the end of 3 years, she will owe a total of $354 for the interest from both loans.
Amount of interest earned at a rate of 4.2% in 3 years would be [tex]0.042\cdot 3\cdot x=0.126x[/tex].
Amount of interest earned at a rate of 6.8% in 3 years would be [tex]0.068\cdot 3\cdot y=0.204y[/tex].
We can represent this information in an equation as:
[tex]0.126x+0.204y=354...(2)[/tex]
Upon substituting equation (1) in equation (2), we will get:
[tex]0.126x+0.204(2500-x)=354[/tex]
[tex]0.126x+510-0.204x=354[/tex]
[tex]-0.078x+510=354[/tex]
[tex]-0.078x+510-510=354-510[/tex]
[tex]-0.078x=-156[/tex]
[tex]\frac{-0.078x}{-0.078}=\frac{-156}{-0.078}[/tex]
[tex]x=2000[/tex]
Therefore, Michelle borrowed $2000 at 4.2%.
Upon substituting [tex]x=2000[/tex] in equation (1), we will get:
[tex]y=2500-2000=500[/tex]
Therefore, Michelle borrowed $500 at 6.8%.
She borrowed $ 2000 from the 4.2% lender and $ 500 from the 6.8% lender.
Since Michelle borrows a total of $ 2500 in student loans from two lenders, and one charges 4.2% simple interest and the other charges 6.8% simple interest, and she is not required to pay off the principal or interest for 3 yr, but at the end of 3yr, she will owe a total of $ 354 for the interest from both loans, to determine how much did she borrow from each lender, the following calculation must be performed:
- 4.2 x 3 = 12.6
- 6.8 x 3 = 20.4
- 2500 x 0.126 + 0 x 0.204 = 315
- 2000 x 0.126 + 500 x 0.204 = 354
Therefore, she borrowed $ 2000 from the 4.2% lender and $ 500 from the 6.8% lender.
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