Answer:
[tex]Q=202.5J[/tex]
Explanation:
Hello,
In this case, the increase in the temperature involves the addition of heat that is defined in terms of mass, heat capacity and temperature:
[tex]Q=mCp(T_2-T_1)[/tex]
In this case, the heat capacity of iron is 0.450 J/(g*K), thus the heat results:
[tex]Q=75g*0.450\frac{J}{g*K}*(301-295)K\\\\Q=202.5J[/tex]
In such a way, since the temperature is increased heat is added, that is why it is positive.
Best regards.
Answer:
q = 202.5 joules
Explanation:
The amount of energy absorbed as one heat 75 grams of iron from 295 k to 301 k can be computed below
q = mcΔt
where
q = energy
m = mass
c = specific heat capacity
Δt = change in temperature
Δt = final temperature - initial temperature
Δt = 301 - 295 = 6 k
c = 0.45 J/g K
q = 75 g × 0.45 J/g K × 6 K
g cancels g and k cancels k we are left with the unit in joules
q = 202.5 joules
