What is the equation of the line passing through the points (–25, 50) and (25, 50) in slope-intercept form? What is the equation of the line passing through the points (–25, 50) and (25, 50) in slope-intercept form? y = negative 50 x y = negative 50 y = 50 x y = 50y = negative 50 x y = negative 50 y = 50 x y = 50

Respuesta :

Answer:

[tex]y = 50[/tex]

Step-by-step explanation:

The slope of the line is:

[tex]m = \frac{\Delta y}{\Delta x}[/tex]

[tex]m = \frac{50 - 50}{25 - (-25)}[/tex]

[tex]m = 0[/tex]

Which means that line is horizontal, whose expression is:

[tex]y = 50[/tex]

Answer:

y = 50 .... The equation of the line

Step-by-step explanation:

Solution:-

- The slope-intercept form for an equation of line is given as:

                          y = m*x + c

Where,

             m : Slope of the line

             c : Intercept of the line.

- We are given two points that lie on the line as follows:

 

            ( x1 , y1 ) = ( -25 , 50 )     &     ( x2 , y2 ) = ( 25 , 50 )

- To determine the slope of the line ( m ), the following formula is used:

             m = ( y2 - y1 ) / ( x2 - x1 )

             m = ( 50 - 50 ) / ( 25 - ( -25 ) )

             m = 0 / 50

             m = 0  

- The slope m = 0, means that the line is perfectly horizontal defined by the y = intercept ( c ):

            y = c    ,      ( -25 , 50 )

            50 = c

Hence,

            y = 50 .... The equation of the line

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