Question

You have the equations:


2H2O(l)→2H2(g)+O2(g), △H=572 kJ


2N2(g)+3H2(g)→2NH3(g), △H=−138 kJ

2NO2(g)+7H2(g)→2NH3(g)+4H2O(l), △H=−1.18×103 kJ 2NO2(g)→2N2(g)+2O2(g), △H=□




What is the missing △H ?


−1.38×103 kJ

+99.0 kJ

+1.38 × 10³ kJ

−138 kJ

Answer 1

Answer:

the answer is 99.0kJ

Explanation:

I took the test in chemistry