According to the question,
We know the formula,
→ [tex]q = m\Delta H[/tex]
By substituting the values,
[tex]2083 = 5.26\times \Delta H[/tex]
[tex]\Delta H = \frac{2083}{5.26}[/tex]
[tex]= 396 \ J/g[/tex]
Thus the above answer is appropriate.
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