Question

You're at a clothing store that dyes your clothes while you wait. You get to pick from

4

44 pieces of clothing (shirt, pants, socks, or hat) and

3

33 colors (purple, blue, or orange).

If you randomly pick the piece of clothing and the color, what is the probability that you'll end up with socks that aren't blue?

Answer 1

Answer:

The probability that you'll end up with socks that aren't blue is $\frac{1}{6}$.

Step-by-step explanation:

The pieces of clothing available:

X = {shirt, pants, socks and hat}

The color options:

Y = {purple, blue and orange}

So, if a person picks a shirt he/she has 3 color options.

Similarly for pants, socks and hat there are 3 color options each.

That makes 12 possible pieces of clothing.

That is, there are 12 total options available.

Now, compute the probability of selecting a socks as follows:

$P(Socks)=\frac{1}{4}$

Compute the probability of selecting the color blue as follows:

$P(Blue)=\frac{1}{3}$

Compute the probability of selecting a socks that are not blue as follows:

$P(Socks\cap not\ Blue)=P(Socks)\times [1-P(Blue)]$

                                  $=\frac{1}{4}\times [1-\frac{1}{3}]$

                                  $=\frac{1}{4}\times \frac{2}{3}$

                                  $=\frac{1}{6}$

Thus, the probability that you'll end up with socks that aren't blue is $\frac{1}{6}$.

Answer 2

Answer:

i got 1/12 on. my khan one

Step-by-step explanation: