Question

rewrite as a quotient of two base - 9 logarithms. write your answer in simplest form log 17 =
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Answer 1

Answer:

$\frac{log_{9}17 }{log_{9}10 }$

Step-by-step explanation:

Using the change of base rule for logarithms

$log_{b}$ x = $\frac{log_{c}x }{log_{c}b }$ ( where c is the new base )

Given

log 17 , that is $log_{10}$ 17 , then

$log_{10}$ 17 = $\frac{log_{9}17 }{log_{9}10 }$