Question

Keisha and David each found the same value for cosine theta, as shown below, given Sine theta = Negative StartFraction 8 Over 17 EndFraction. Keisha’s Solution David’s Solution Tangent squared theta + 1 = secant squared theta. StartFraction sine squared theta Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. StartFraction (eight-seventeenths) squared Over cosine squared theta EndFraction + 1 = StartFraction 1 Over cosine squared theta EndFraction. (eight-seventeenths) squared + cosine squared theta = 1. cosine theta = plus-or-minus StartRoot 1 minus StartFraction 64 Over 289 EndFraction EndRoot. cosine theta = plus-or-minus Fifteen-seventeenths sine squared theta + cosine squared theta = 1. cosine squared theta = 1 minus (negative eight-seventeenths) squared. cosine theta = plus-or-minus StartRoot StartFraction 225 Over 289 EndFraction EndRoot. Cosine theta = plus-or-minus fifteen-seventeenths Whose procedure is correct?

Answer 1

Answer

They are both correct

Step-by-step explanation:

Answer 2

Keisha and the David.

As per the question Kisha and the David found the same value of the cosine theta as given by the  Sine theta = Negative Start Fraction 8 Over 17 End Fraction. The Keisha solution and the Davis solution for the solution were tan-squared (theta) + 1 = sec-squared (theta).
Thus the answer is both procedures are correct.

• As they both wanted to find the solutions to the numerical problems they made two different methods.
  
• Such as the Sine theta = Negative Start Fraction and the tan-squared (theta) + 1 = sec-squared (theta).

• Hence both options are the same and true.

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