Answer:
0.20M HCl
Explanation:
The reaction of neutralization of NaOH with HCl is:
NaOH + HCl → H₂O + Cl⁻ + Na⁺
Where 1 mole of NaOH reacts with 1 mole of HCl.
Moles of 10.0 mL of a 0.50 M NaOH solution are:
0.0100L × (0.50moles NaOH / 1L) = 0.0050 moles of NaOH
As 1 mole of NaOH reacts with 1 mole of HCl, at equivalence point, moles of HCl are 0.0050 moles.
If volume of HCl is 25.0mL, concentration is:
0.0050 mol / 0.025L = 0.20M HCl
