Given triangle XYZ will follow the midsegment theorem.
By this theorem, statements given in options (2), (4) and (5) are correct.
From the picture attached,
ΔXYZ will follow the midsegment theorem which states,
"Segment connecting the midpoints of two sides of a triangle is parallel and half of the third side of the triangle"
- BC = [tex]\frac{1}{2}XY[/tex]
- AC = [tex]\frac{1}{2}YZ[/tex]
- AB = [tex]\frac{1}{2}XZ[/tex]
- CB ║XY
- AC ║YZ
- AB ║XZ
Therefore, Options (2), (4) and (5) are the correct options.
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