Question

After an initial push, a sled begins to move downhill at 1 m/s. A few seconds later its kinetic energy has increased. The sled now has 64 times more kinetic energy than it did right after the push. How fast it it going?

Answer 1

1/6 is how much your neighbor will have the answer would be 8

Answer 2

At present, the velocity of the sled is 1/8 m/sec and this can be determined by using the formula of the kinetic energy.

Given :

• After an initial push, a sled begins to move downhill at 1 m/s.
• A few seconds later its kinetic energy has increased.
• The sled now has 64 times more kinetic energy than it did right after the push.

The kinetic energy is given by the equation:

$\rm KE = \dfrac{1}{2}mv^2$

where KE is the kinetic energy, m is the mass, and v is the velocity.

The Kinetic energy of the sled right after the push is given by:

$\rm KE = \dfrac{1}{2}\times m\times (1)^2$

Now, according to the given data, the sled now has 64 times more kinetic energy than it did right after the push, that is:

(KE) = 64 (KE)'

Now, substitute the values of the known terms in the above expression in order to determine the value of v'.

$\rm \dfrac{1}{2}\times m \times (1)^2=64\times \dfrac{1}{2}\times m \times (v')^2$

$\rm v' = \sqrt{ \dfrac{1}{64}}$

$\rm v'=\dfrac{1}{8} \; m/sec$

For more information, refer to the link given below:

https://brainly.com/question/15764612