Question

Find two positive even consecutive integers is 132 such that the square of the smaller integer is 10 more than the larger integer.

Answer 1

Answer:

Step-by-step explanation:

n(n + 1) = 132 (n + 10)(n - 11) = 0

+ n = 132 n = -10 or n = 11.

+ n – 132 = 0