Respuesta :
Answer:
Heat Energy produced in one year of operation is 6.758 x 10¹⁶ J
Explanation:
Given;
rate of power generation, E = 7.50 × 10⁸ J/s
overall efficiency, η = 35%
To determine the amount of heat energy in joules produced in one year of operation;
first: convert one year to seconds
Assume there are 365 days in one year,
365 days x 24 hours x 60 minutes x 60 seconds = 31536000 s
Heat Energy produced in one year of operation at given rate = (7.50 × 10⁸ J/s) x (31536000 s)
= 2.3652 x 10¹⁶ J
Heat Energy produced in one year of operation at given efficiency =
(2.3652 x 10¹⁶ J) / (0.35) = 6.758 x 10¹⁶ J
Therefore, Heat Energy produced in one year of operation is 6.758 x 10¹⁶ J
The amount of heat energy in Joules that is produced in one year of operation is [tex]6.83 \times 10^{16}[/tex] Joules.
Given the following data:
- Power = 750 megawatts (MW) or [tex]7.50 \times 10^8[/tex] J/s.
- Overall efficiency = 35%
To find the amount of heat energy in Joules that is produced in one year of operation:
First of all, we would determine the time duration in seconds.
1 year = 365 days = 31536000 seconds
Next, we would determine the energy generated within this time frame or period.
Mathematically, energy is given by the formula:
[tex]Energy = Power \times time[/tex]
Substituting the given parameters into the formula, we have;
[tex]Energy = 7.50 \times 10^8 \times 31536000\\\\Energy = 2.39 \times 10^{16}\; Joules[/tex]
Heat energy at an overall efficiency of 35%:
[tex]Heat\;energy = \frac{Energy\;produced}{Efficiency}\\\\Heat\;energy = \frac{2.39 \times 10^{16}}{0.35}[/tex]
Heat energy = [tex]6.83 \times 10^{16}[/tex] Joules
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