Answer:
[tex]\frac{Q_{square}}{Q_{circle}} = 0.785[/tex]
Explanation:
given data
types of drinking straws
solution
we know that both perimeter of the cross section are equal
so we can say that
perimeter of square = perimeter of circle
4 × S = π × D
here S is length and D is diameter
S = [tex]\frac{\pi D}{4}[/tex] ....................1
and
ratio of flow rate through the square and circle is here
[tex]\frac{Q_{square}}{Q_{circle}} = \frac{AV^2}{AV^2}[/tex]
[tex]\frac{Q_{square}}{Q_{circle}} = \frac{S^2}{\frac{\pi D^2}{4}}[/tex]
[tex]\frac{Q_{square}}{Q_{circle}} = \frac{(\frac{\pi D}{4})^2}{\frac{\pi D^2}{4}}[/tex]
[tex]\frac{Q_{square}}{Q_{circle}} = \frac{\pi }{4}[/tex]
[tex]\frac{Q_{square}}{Q_{circle}} = 0.785[/tex]