Question

what happens if 0.87 mol NaCl is dissolved in pure water creating 3.00 L of solution, what is its molarity of the resulting solution?

Answer 1

Answer:

The molarity of the resulting solution is 0.29 mol/L

Explanation:

Given:

nNaCl = moles = 0.87 mol

V = volume of solution = 3 L

Question: What is its molarity of the resulting solution, M = ?

First, you need to know that the molarity of a solution is the number of moles of the solute, in this case the salt (NaCl), divided by the volume of the solution:

$M=\frac{n_{NaCl} }{V} =\frac{0.87}{3} =0.29 mol/L$

Answer 2

Answer:

$M=0.29M$

Explanation:

Hello,

In this case, we define the formula of molarity which is an unit of concentration allowing us to relate the moles of the solute which in this case is the sodium chloride (NaCl) with the volume of the solution in liters:

$M=\frac{n}{V}$

Thus, with the given data, the resulting molarity in molar units (mol/L) is:

$M=\frac{0.87mol}{3.00L}\\ \\M=0.29mol/L\\M=0.29M$

Best regards.