Respuesta :
Answer:
Part B : Hg
Part C : Ag
Explanation:
When we added ammonium hydroxide to the solid remains after addition hot water , AgCl dissolve due to the formation of soluble complex [Ag(NH3)2]+ and Hg2Cl2 gives black precipitate with ammonium hydroxide due to formation of elemental mercury.
Black precipitate is not formed upon addition of amonium hydroxide to the precipitate remains after addition of hot water, so Hg22+ is shown not to be present.
The precepite remains after addition of hot water is dissolved by the addition of ammonium hydroxide, so Ag+ may be present. The presence of Ag+ is not confiremed by K2CrO4 test.
When The solution is acidic by concentrated Nitric acid forms the white precipitate, which shows the presence of Lead cation group 1
What is Ammonium Hydroxide?
The unknown sample + HCl -----> precipitate forms
The formation of precipitate on treatment with HCl confirms the presence of Group 1
Precipitate + boiling water ------> some solid disappears
If some of the solid disappear in this step, it conducts lead may be present
decant the solution, solid + drops of K2Cr2O7----> no yellow color solid
solid left + ammonium hydroxide + centrifuge ---> no grey / black solid
decant the solution + add con-c Nitric acid -----> White Precipitate forms (lead present)
The above analysis shows the presence of Lead cation in group 1
and absence of Mercury and silver cation of group 1
Group 1 contains three cations lead, silver, and mercury.
According to the scheme of cation analysis on treatment with HCl -----> Precipitate forms
It may contain AgCl, PbCl2 or Hg2Cl2
Precipitate + hot water -----> Precipitate forms ( silver or Mercury may be present)
If ppt dissolves then lead may be attending
additionally on treatment with ammonium hydroxide, centrifugation, and then producing the solution acidic by consolidated Nitric acid forms the white precipitate, which shows the existence of Lead cation.
Find more information about Ammonium Hydroxide here:
https://brainly.com/question/22547992