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Following are the solution to the given question:
Assume three balanced coins were tossed at random, and its sampling area is identified as:
[tex]\bold{S=\{HHH,HHT,HTH,HTT,THH, THT,TTH,TTT\}}[/tex]
Let [tex]Y_1[/tex] consider the head number; the choices for [tex]Y_1[/tex] are 0, 1, 2, and 3.
In other words,
[tex]Value \ \ \ \ \ \ \ outcome \\\\0 \ \ \ \ \ \ \ \ \ \ TTT\\\\1 \ \ \ \ \ \ \ \ \ \ HTT,THT,TIH\\\\2 \ \ \ \ \ \ \ \ \ \ HHT,THH, HTH\\\\3 \ \ \ \ \ \ \ \ \ \ HHH\\\\[/tex]
Let [tex]Y_2[/tex] symbolize the amount of money won on the winning bet in the following way.
- When players get the first heads on the first toss, they gain [tex]\$1.[/tex]
- When you get the first head-on toss 2 or toss 3, you win[tex]\$2 \ or\ \$3[/tex], respectively.
- When no heads emerge, you lose [tex]\$1 (win - \$1)[/tex].
- [tex]Y_2[/tex] has the following possibilities: [tex]-1,1,2,3[/tex]
That is,
[tex]Value \ \ \ \ \ \ \ \ \ \ outcome\\\\-1 \ \ \ \ \ \ \ \ \ \ \ \ TTT\\\\1 \ \ \ \ \ \ \ \ \ \ \ \ HTT, HHT,HTH,HHH\\\\2 \ \ \ \ \ \ \ \ \ \ \ \ \ THT,THH\\\\3 \ \ \ \ \ \ \ \ \ \ \ \ \ TTH\\\\[/tex]
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