Answer:
13g
Explanation:
Step 1:
The equation for the reaction. This is given below:
C4H10 + O2 —> CO2 + H2O
Step 2:
Balancing the equation. The equation can be balanced as follow:
C4H10 + O2 —> CO2 + H2O
There are 4 atoms of C on left side and 1 atom on the right side. It can be balance by putting 4 in front of CO2 as shown below:
C4H10 + O2 —> 4CO2 + H2O
There are 10 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 5 in front of H2O as shown below:
C4H10 + O2 —> 4CO2 + 5H2O
There are a total of 13 atoms of O on the right side and 2 atoms on the left side. It can be balance by putting 13/2 in front of O2 as shown below:
C4H10 + 13/2O2 —> 4CO2 + 5H2O
Multiply through by 2 to clear the fraction
2C4H10 + 13O2 —> 8CO2 + 10H2O
Now the equation is balanced.
Step 3:
Determination of the masses of C4H10 and O2 that reacted from the balanced equation. This is illustrated below:
2C4H10 + 13O2 —> 8CO2 + 10H2O
Molar Mass of C4H10 = (12x4) + (10x1) = 48 + 10 = 58g/mol
Mass of C4H10 from the balanced equation = 2 x 58 = 116g
Molar Mass of O2 = 16x2 = 32g/mol
Mass of O2 from the balanced equation = 13 x 32 = 416g
From the balanced equation above, 116g of C4H10 reacted will 416g of O2.
Step 4:
Determination of the mass of C4H10 that will react with 43.8 g of O2. This is illustrated below:
From the balanced equation above, 116g of C4H10 reacted will 416g of O2.
Therefore, Xg of C4H10 will react with 43.8g of O2 i.e
Xg of C4H10 = (116 x 43.8)/416
Xg of C4H10 = 12g
Therefore, 12g of C4H10 reacted with 43.8g of O2.
Step 5:
Determination of the leftover Mass of C4H10. This is illustrated below:
Mass of C4H10 given = 25g
Mass of C4H10 that reacted = 12g
Mass of C4H10 remaining =?
Mass of C4H10 remaining = (Mass of C4H10 given) - (Mass of C4H10 that reacted)
Mass of C4H10 remaining = 25 - 12
Mass of C4H10 remaining = 13g
