Determine the binding energy per nucleon of an Mg-24 nucleus. The Mg-24 nucleus has a mass of 23.985045. A proton has a mass of 1.00728 amu, a neutron has a mass of 1.008665 amu, and 1 amu is equivalent to 931.5 MeV of energy. Determine the binding energy per nucleon of an Mg-24 nucleus. The Mg-24 nucleus has a mass of 23.985045. A proton has a mass of 1.00728 amu, a neutron has a mass of 1.008665 amu, and 1 amu is equivalent to 931.5 MeV of energy.

a.8.01 MeV
b.192 MeV
c.0.113 MeV
d.4.41 MeV
e.0.3050 MeV

Respuesta :

Answer:

192.16MeV

Explanation:

Mass of neutron (Mn) = 1.008665 amu

Mass of proton (Mp) = 1.00728 amu

Mass of nucleus (Mg-24) = 23.985045 amu

1 amu = 931.5MeV

Binding energy of the nucleus is the work or energy needed just to take all the entire nucleons apart so that they are completely separated.

Mass defect = (mass of proton + mass of neutron) - mass of nucleus.

Mass defect = [12(1.00728) + 12(1.008665)] - 23.985045

Mass defect = [(12.08736 + 12.10398)] - 23.985045

Mass defect = 24.19134 - 23.985045

Mass defect = 0.206295amu

Binding energy = mass defect * 931.5 MeV

Binding energy = 0.206295 * 931.5

Binding energy = 192.16MeV

The binding energy per nucleon of an Mg-24 nucleus is;

D. 4.41 MeV

We are given;

Molar mass of Mg-24; M = 24.30506 amu

Number of protons = 12 protons

Number of neutrons = 12 neutrons.

Molar mass of hydrogen is 1.00728 amu

Thus;

Hydrogen atom mass = 12 × 1.00728 amu

Hydrogen atom mass = 12.0874 amu

Neutron mass = 12 x 1.008665 amu

Neutron mass = 12.104 amu

Formula for theoretical mass is;

Theoretical mass = Hydrogen atom mass + Neutron mass

Theoretical mass = 12.0874 + 12.104

Theoretical mass = 24.1914 amu

Formula for the mass defect is:

Mass defect = Actual molar mass - Theoretical mass

Mass defect = 24.30506 amu - 24.1914 amu

Mass defect = 0.11366 amu

Formula for the binding energy per nucleon is:

B.E = (Mass defect × energy per amu)/nucleons

B.E = (0.11366 × 931.5)/24

B.E per nucleon = 4.41 MeV

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