Question

In a Young's double-slit experiment, a thin sheet of glass is placed over one of the two slits. As a result, the center of the fringe pattern (on the screen) shifts so that the center is now occupied by what was the 30th dark band. The wavelength of the light in this experiment is 600 nm and the index of the glass is 1.50.
a) The glass thickness is____________.

Answer 1

Answer:

0.036mm

Explanation:

We are given that

Wavelength,$\lambda=600nm=600\times 10^{-9} m$

$1nm=10^{-9} m$

Index of glass=n=1.5

m=30

We have to find the thickness of glass.

Thickness of glass,t=$\frac{m\lambda}{n-1}$

Substitute the values

$t=\frac{30\times 600\times 10^{-9}}{1.5-1}$

$t=0.036\times 10^{-3} m$

$1mm=10^{-3} m$

$t=0.036mm$