A company manufactures mountain bikes. The research department produced the marginal cost function Upper C prime​(x)equals700- x/ 3
​, 0 less than or equals x less than or equals 900​, where Upper C prime​(x) is in dollars and x is the number of bikes produced per month. Compute the increase in cost going from a production level of 450 bikes per month to 900 bikes per month. Set up a definite integral and evaluate it.
The increase in cost is ​$
nothing.

Respuesta :

Answer:

The increase in cost is     [tex]C _{(900 - 450 )} =[/tex] $ 213750      

Step-by-step explanation:

From the question we are told that

    The marginal cost function is  [tex]C \ '(x) = 700 -\frac{x}{3}[/tex]   where [tex]0 \le x \le 900[/tex]

     Since [tex]C \ '(x)[/tex] is in dollars it means that [tex]C(x)[/tex] is the cost price and x is given as  the number of bikes now to obtain [tex]C(x)[/tex]  for the given increase of the  number of bikes we integrate [tex]C\ '(x)[/tex] within the increase limit

 This can be evaluated as

       [tex]\int\limits^{900}_{450} {C \ '(x)} \, dx = \int\limits^{900}_{450} {700 - \frac{x}{3} } \, dx[/tex]

        [tex]C(x) = [ {700x - \frac{x^2}{6} }] \left 900} \atop {450}} \right.[/tex]

         [tex]C _{(900 - 450 )} = [700(900) - \frac{900^2}{6} ] - [700(450) - \frac{450^2}{6} ][/tex]            

        [tex]C _{(900 - 450 )} = 495000- 281250[/tex]      

      [tex]C _{(900 - 450 )} =[/tex] $ 213750      

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