Four U Tubes each have distilled water in the right arm, a solution in the left arm, and a semipermeable membrane between arms. A. If the solute is NaBr, which solution is least concentrated? B. If each solute is different but all the solutions have the same molarity, which contains the largest number of dissolved ions?

(a) If solution and pure solvent are both separated by semi- permeable membrane, osmosis is said to occur from higher concentration to lower concentration of solvent . The solution with the least concentration will absorb least amount of H2O

In the attached file tube C will absorb the least amount of H20, therefore the least concentrated solution is C

(b)The largest number of dissolved ions is said to be in the solution that absorb maximun amount of H2O because osmotic pressure is said to be high in it.

Tube B has the highest number of dissolved ions

kasliwalalvi24 kasliwalalvi24 · Answer 2 · 2021-12-08T08:58:31+01:00

The semi-permeable membrane is a selective membrane, which allows the specific molecules to pass through. In the given question, Tube B will have a high number of dissolved ions.

The answers can be explained as:

(a) The solution and the pure solvent if are separated by a semi-permeable membrane, then the osmosis will take place from the region of higher concentration to the lower concentration of the solvent. Tube C will absorb the least amount of water molecules.

(b) The maximum amount of the water molecule dissolved ions will have the highest osmotic pressure. Osmotic pressure is defined as the minimum pressure applied to prevent the backflow of solvent through a semi-permeable membrane.

Thus, tube B will have the maximum amount of dissolved ions.

To know more about semi-permeable membranes, refer to the following link:

https://brainly.com/question/13793077