Answer:
Option B. is the right choice.
Step-by-step explanation:
[tex]Radius=r=\frac{Diamter}{2}=\frac{8}{2}=4\:in[/tex]
[tex]Total\:Area\:=\:Area\:of\:Circle+Area\:of\:Triangle\\\\=\pi \left(4\right)^2+\frac{1}{2}\left(8\right)\left(8\right)\\\\=16\pi +32\quad \\\\\approx 82\:in^2[/tex]
