Answer:
The monthly payments to be made is $62.50. The total interest that will be paid is $1,513.
Step-by-step explanation:
The formula to compute the monthly payment is:
[tex]A=P\times [\frac{i(1+i)^{n}}{(1+i)^{n}-1}][/tex]
Here,
A = periodic payment
P = principal amount borrowed
i = periodic interest rate
n = number of periods
The information provided is:
P = $2,237
i = 1.88% = 0.0188
n = 60
Compute the value of A as follows:
[tex]A=P\times [\frac{i(1+i)^{n}}{(1+i)^{n}-1}][/tex]
[tex]=2237\times [\frac{0.0188(1+0.0188)^{60}}{(1+0.0188)^{60}-1}][/tex]
[tex]=2237\times 0.02794\\=62.50178\\\approx \$62.50[/tex]
Thus, the monthly payments to be made is $62.50.
The formula to compute the total interest that will be paid is:
[tex]Interest=(A\times n)-P[/tex]
Compute the total interest that will be paid as follows:
[tex]Interest=(A\times n)-P[/tex]
[tex]=(62.50\times 60)-2237\\=3750-2237\\=1513[/tex]
Thus, the total interest that will be paid is $1,513.