Question

For what value of a does g=(1/27)^a+3?

Answer 1

Answer:

-11/3

Step-by-step explanation:

Answer 2

Answer:

-11/3

$9 = { (\frac{1}{27} )}^{a + 3}$

${(3)}^{2} = { ({3}^{ - 3}) }^{a + 3}$

${(3)}^{2} = {(3)}^{ - 3a - 9}$

Since the bases are same, therefore the exponents are equal

2=-3a-9

3a=-9-2

a= -11/3