Respuesta :
Answer:
a. On average, the number of boards they have on order = 1,056 boards.
b. On average, the number of boards they have =560 boards.
c. Total holding cost per week = $140.
d. Holding cost incurred per board = $ 0.25.
Explanation:
In the question, the details given are:
Service level =96 %
Lead time =3 weeks
Weekly demand =150
Standard deviation=200
This is a case of variable demand and constant lead time
a. Reorder point =Demand during lead time +Safety stock
=Average weekly demand*lead time+z*sqrt(lead time)*standard deviation of weekly demand
=150*3+NORMSINV(0.99)*sqrt(3)*200
=450+1.7507*sqrt(3)*200
=450+606.46=1,056.46
=1,056 (nearest whole number).
On average, the number of boards they have on order = 1,056 boards.
b. For a normal distribution,
z=x-mean/std deviation
z-value for a 96% confidence level = 2.05
2.05=x-150/200
x = 150+2.05*200=560
On average, the number of boards they have =560 boards.
c.Total holding cost per week=Average inventory *holding cost per week=560/2 *0.5=280*0.5 =$140
d.Holding cost incurred per board =Total holding cost /Number of boards =140/560 = $ 0.25.
A. On average, the number of boards they have on order is = 1,056 boards.
B. On average, the number of boards they have is = 560 boards.
C. The Total holding cost per week is = $140.
D. Then the Holding cost incurred per board is = $0.25.
What is the Holding cost?
As per the given information In the question, the details are:
The Service level is =96 %
Lead time is = 3 weeks
Weekly demand is =150
The standard deviation is =200
This is a case of variable demand and also the constant lead time
A. When the Reorder point is = Demand during lead time + Safety stock
Then = the Average weekly demand*lead time+ z × sqrt(lead time) × standard deviation of weekly demand is =150 × 3+NORMSINV(0.99) × sqrt(3) × 200
After that =450+1.7507×sqrt(3)×200
Then =450+606.46=1,056.46
So that, =1,056 (nearest whole number).
On average, the number of boards they have on order is = 1,056 boards.
B. Now, For a normal distribution,
z is =x-mean/std deviation
After that z-value for a 96% confidence level is = 2.05
then 2.05=x-150/200
then x is = 150+2.05×200=560
On average, the number of boards they have is = 560 boards.
C. Then Total holding cost per week is =Average inventory ×holding cost per week is = 560/2 ×0.5=280×0.5 =$140
D. Then Holding cost incurred per board is =Total holding cost /Number of boards =140/560 = $ 0.25.
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