Question

On a coordinate plane, 2 lines are shown. Line P Q has points (negative 8, 2) and (4, 2). Line M N has points (8, 6) and (8, negative 8). What is the slope of line PQ? What is the slope of line MN? How are the two lines related?

Answer 1

Answer:

first is 0

then undefined

last the lines are perpendicular

Answer 2

The slope of the line PQ is 0

The slope of the line MN is ∞

The line PQ is a horizontal line while the line MN is a vertical line

The formula for calculating the slope of the line is expressed as:

$m = \frac{y_2-y_1}{x_2-x_1}$

For the line PQ with the coordinates (-8, 2) and (4, 2)

$m_{PQ} = \frac{2-2}{4-(-8)} \\m_{PQ} = \frac{0}{12} \\m_{PQ} = 0$

Similarly for the line MN with coordinates

$m_{MN} = \frac{-8-6}{8-8)} \\m_{MN} = \frac{-14}{0} \\m_{MN} = \infty$

The line PQ is a horizontal line while the line MN is a vertical line

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