Respuesta :
Answer:
The molarity of the solution is = 4.31 M
Explanation:
To find the molarity within a solution, the equation is used:
- M = Moles of solute / Liters of solution
- The first thing we have to do is convert the grams of NaOH to moles. And the mL of solution in liters of solution.
- 32.02g of NaOH ÷ 39.997 g / mol = 0.801 mol NaOH
- 186 mL of solution = 0.186L of solution
- Now with the data the molarity equation is solved:
- M = 0.801 ÷ 0.186
- M = 4.306
- Approaching would give that:
- M = 4.31
Answer:
Molarity = 4.31 M
Explanation:
Data:
mass NaOH = 32.02 g
solution volume = 186 mL = 0.186 L
MW NaOH = 39.99 g/mol
The equation for calculating molarity is as follows:
[tex]M=\frac{solute moles}{solution volume}[/tex]
To calculate the moles of NaOH we use the following equation:
[tex]MW=\frac{mass}{moles}[/tex]
Where MW is the molecular weight of the solute.
We clear the moles of the previous equation:
[tex]moles=\frac{mass}{MW}[/tex]
Where the molecular weight of NaOH is 39.99 g/mol.
[tex]moles=\frac{32.02g}{39.99\frac{g}{mol} }=0.801mol[/tex]
We substitute the values of moles and volume in the molarity equation.
[tex]M=\frac{0.801mol}{0.186L}=4.31M[/tex]
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