Respuesta :
I suppose you mean to find the value of the expression (not function) sin(14π/10).
To start, 14/10 = 7/5.
Next, expand sin(7x) using the angle sum identity,
[tex]\sin(\alpha+\beta)=\sin\alpha\cos\beta+\sin\beta\cos\alpha[/tex]
This lets us write
[tex]\sin(7x)=\sin x\cos(6x)+\sin(6x)\cos x[/tex]
and we can keep applying the identity to the multiple-angle argument to wind up with
[tex]\sin(7x)=7\cos^6x\sin x-35\cos^4x\sin^3x+21\cos^2x\sin^5x-\sin^7x[/tex]
We can replace [tex]\cos^2x=1-\sin^2x[/tex] to write this in terms of sin(x) only.
[tex]\sin(7x)=7\sin x-56\sin^3x+112\sin^5x-64\sin^7x[/tex]
Then we can find the value of sin(7π/5) by plugging in π/5. But to do that, we need to first find the value of sin(π/5).
Using the same process as above, we have
[tex]\sin(5x)=\sin x\cos(4x)+\sin(4x)\cos x=\cdots[/tex]
[tex]\sin(5x)=5\cos^4x\sin x-10\cos^2x\sin^3x+\sin^5x[/tex]
[tex]\sin(5x)=5\sin x-20\sin^3x+16\sin^5x[/tex]
When x = π/5, the left side reduces to sin(π) = 0. Let y = sin(π/5). Then
[tex]0 = 5y-20y^3+16y^5[/tex]
Factorize the right side:
[tex]0=5y(1-4y^2+3y^4)=5y(5-20y^2+16y^4)[/tex]
Solving for y tells us that either y = 0 (which can't be true, because 0 < π/5 < π/2 means 0 < sin(π/5) < 1), or
[tex]16y^4-20y^2+5=0[/tex]
Using the quadratic formula, we find
[tex]y^2=\dfrac{5\pm\sqrt5}8[/tex]
[tex]\implies y=\pm\sqrt{\dfrac{5\pm\sqrt5}8}[/tex]
or 4 possible values, approximately -0.5878, 0.5878, -0.9512, or 0.9512.
Of course, only one of these values can be correct. We know sin(π/5) should be positive, so we throw out the two negative options. Also, sin(x) is strictly increasing over (0, π/2). This means 0 < π/5 < π/4 tells us 0 < sin(π/5) < sin(π/4), and sin(π/4) is approximately 0.707. Then sin(π/5) must be 0.5878, or exactly
[tex]\sin\dfrac\pi5=\sqrt{\dfrac{5-\sqrt5}8}[/tex]
Now plug this into the identity we found for sin(7x).
[tex]\sin\left(\dfrac{7\pi}5\right)=7\sin\left(\dfrac\pi5\right)-56\sin^3\left(\dfrac\pi5\right)+112\sin^5\left(\dfrac\pi5\right)-64\sin^7\left(\dfrac\pi5\right)[/tex]
[tex]\implies\sin\left(\dfrac{7\pi}5\right)=-\sqrt{\dfrac{5+\sqrt5}8}[/tex]
Answer:
The answer is -0.95
Step-by-step explanation:
I just took the test on edg and got it correct.
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